Methane Cylinder Pressure Under Fire: 1080atm/1568psi

AI Thread Summary
The discussion focuses on calculating the pressure of a methane cylinder under extreme heat conditions, starting from an initial pressure of 200 atmospheres at 0°C. When the temperature rises to 1200°C, the ideal gas law is applied, leading to the conclusion that the final pressure is approximately 1080 atmospheres. Participants clarify that the volume does not need to be evaluated since the number of moles is not provided, and they emphasize the importance of unit conversions. The ideal gas law relationship P1/T1 = P2/T2 is highlighted as a key formula for this calculation. Overall, the calculations demonstrate how temperature significantly affects gas pressure in high-stress scenarios.
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Consider a high pressure gas cylinder of methane which exhibits a pressure of 200 atmosphers (absolute) at a temp. of 0*C in a small storage building. the building catches fire whcih causes the temp of the cylinder to rise to 1200*C. What would the pressure in the cylinder be then? express your answer in both atmopheres and in psi(lbf/in^2), assume methane behaves as an ideal gas.

ok. seems easy. but I am confused about this whole ideal gas thing. do i always use (0.08205 atmos. liters/ mole K) for R?

if so then would i do...

(P1)(V)=(R)(T1) = (200)(V)=(0.08205)(273)
so, V = ((0.08205)(273))/(200) = 0.1119
but this number seems unlikley. but if so
(P2)(V)=(R)(T2) = (P2)(0.1119)=(0.08205)(1473)
so. P2 = 1080atm? am i doing this somewhat right?
 
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you don't need to evaluate the volume in this problem, since you don't have the molar number.
PV=nRT implies P/T=nR/V
whereas the right hand side is constant... therefore, you have
P_{i}/T_{i}=P_{f}/T_{f}
 
The result looks good now pay attention with unit conversion...

Daniel.
 
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