Methods of Section: Truss problem

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SUMMARY

The discussion focuses on solving the truss problem by determining the forces in members AC and BC using the methods of section. Key variables include distances AB (79 cm), BC (63 cm), AC (98 cm), and a downward force of 39.94N at point C. The participants emphasize the importance of correctly applying the equations of equilibrium, specifically ΣFx, ΣFy, and ΣMa, to analyze the forces and moments at point A and the roller support at point B.

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  • Understanding of static equilibrium principles
  • Familiarity with the methods of sections in truss analysis
  • Knowledge of calculating moments and forces in structural analysis
  • Ability to interpret free-body diagrams
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  • Study the methods of sections in truss analysis
  • Learn how to create and analyze free-body diagrams for trusses
  • Explore the application of ΣFx and ΣFy equations in structural mechanics
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Engineering students, structural analysts, and anyone involved in mechanical or civil engineering who seeks to understand truss analysis and the methods of section for determining internal forces.

SagarPatil
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1. The problem statement,
Have to find the forces in AC & BC using the methods of section.

all variables and given/known data

Distance
AB = 79cm
BC = 63
AC = 98
d = 3.833
AZ = 62.881
ZC = 75.16

Point B is a roller and point A is a Pin

Whats given is 39.94N Forces @ C going down

Homework Equations


ΣFx
ΣFy
ΣMa

The Attempt at a Solution


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upload_2015-9-22_22-33-8.png
 

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You appear to have cut through BC and AC, and are analyzing the part with point C.
Your reaction forces at the wall appear to be correct.
I suggest analyzing the part next to the wall.
 
insightful said:
You appear to have cut through BC and AC, and are analyzing the part with point C.
Your reaction forces at the wall appear to be correct.
I suggest analyzing the part next to the wall.

If I take moment at point A does Bx cancel ?
BC I calculated is correct?
 
SagarPatil said:
If I take moment at point A does Bx cancel ?
BC I calculated is correct?
You have BC=Bx, which cannot be. If I read your drawing right, Bx=31.79 (I agree) and taking the moments around A of the section next to the wall tells you this must cancel the horizontal component of BC.
 
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insightful said:
You have BC=Bx, which cannot be. If I read your drawing right, Bx=31.79 (I agree) and taking the moments around A of the section next to the wall tells you this must cancel the horizontal component of BC.

I got the answer. I didn't understand the concept first. After reading I got it :D
 

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