- #1
linda300
- 61
- 3
Hey guys,
I have been working on the following question:
http://imageshack.us/a/img407/4890/81345604.jpg
For part a
f and g are continuous on I
=> there exists e > 0 and t_0 s.t.
0<|{f(t) - g(t)} - {f(t_0) - g(t_0)}| < e
using |a-b| >= |a| - |b|,
|{f(t) - g(t)} - {f(t_0) - g(t_0)}| >= |{f(t) - g(t)}| - |{f(t_0) - g(t_0)}|
and
|{f(t) - g(t)}| - |{f(t_0) - g(t_0)}| >= |{f(t) - g(t)}| - |f(t_0)| + |g(t_0)|
but I'm not sure where to go from here, I have tried a lot of different steps but I end up going in circles or getting back to the triangle inequality haha.
Does anyone have any ideas on how to do this? Is there some simple trick that I am just missing?
For part b,
Proving σ>=τ is pretty straight forward, just applying the Schwarz inequality but I'm having trouble showing that ρ>σ
How can you relate that sup to the integral expression σ?
Thanks in advance
I have been working on the following question:
http://imageshack.us/a/img407/4890/81345604.jpg
For part a
f and g are continuous on I
=> there exists e > 0 and t_0 s.t.
0<|{f(t) - g(t)} - {f(t_0) - g(t_0)}| < e
using |a-b| >= |a| - |b|,
|{f(t) - g(t)} - {f(t_0) - g(t_0)}| >= |{f(t) - g(t)}| - |{f(t_0) - g(t_0)}|
and
|{f(t) - g(t)}| - |{f(t_0) - g(t_0)}| >= |{f(t) - g(t)}| - |f(t_0)| + |g(t_0)|
but I'm not sure where to go from here, I have tried a lot of different steps but I end up going in circles or getting back to the triangle inequality haha.
Does anyone have any ideas on how to do this? Is there some simple trick that I am just missing?
For part b,
Proving σ>=τ is pretty straight forward, just applying the Schwarz inequality but I'm having trouble showing that ρ>σ
How can you relate that sup to the integral expression σ?
Thanks in advance
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