Minimum d occurs at minimum d^2

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Homework Statement


Find the point on the parabola y^2 = 2x that is closest to the point (1,4)

Homework Equations


d = ((x-1)^2 + (y-4)^2)^1/2
x=y^2/2

The Attempt at a Solution


My attempt involves subbing in x in the d equation and differentiating it. I can't get the same answer as the book because they differentiate d^2 = not d = to make it easier to solve.
They state "you should convince yourself the minimum of d occurs at the same point as the minimum of d^2, but d^2 is easier to work with"

How do i know it occurs at the same point?
 
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Try to find positive ##d_1 < d_2## with ##d_1^2 > d_2^2##
 
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brycenrg said:

Homework Statement


Find the point on the parabola y^2 = 2x that is closest to the point (1,4)

Homework Equations


d = ((x-1)^2 + (y-4)^2)^1/2
x=y^2/2

The Attempt at a Solution


My attempt involves subbing in x in the d equation and differentiating it. I can't get the same answer as the book because they differentiate d^2 = not d = to make it easier to solve.
They state "you should convince yourself the minimum of d occurs at the same point as the minimum of d^2, but d^2 is easier to work with"

How do i know it occurs at the same point?
If ##0<a<b## then ##a\cdot a < a \cdot b < b\cdot b##.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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