Minimum stopping distance problem

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SUMMARY

The minimum stopping distance for a load of steel with a mass of 6000 kg on a truck traveling at 20 m/s is calculated to be 150 meters. This is determined by first calculating the acceleration using the maximum horizontal force of 8000 N, resulting in an acceleration of -1.33 m/s². The time to stop is found to be 15 seconds, which is then used to compute the stopping distance using the equation x = x₀ + v₀t + 0.5at².

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A load of steel of mass 6000kg rests on the flatbed of a truck. It is held in place by metal brackets that can exert a maximum horizontal force of 8000 N. When the truck is traveling 20 m/s, what is the minimum stopping distance if the load is not to slide forward into the cab?
 
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ok here how i did it,...im gettin an answer of 150m

first find the acceleration in the negative x direction the brackets can exert which is.
8000=(6000)a

a= -1.33


then find the time it takes to stop using v=vo +at

0= 20 + (-1.33) t t= 15sec


then find distance using x=xo +volt+.5at^2



x = 20(15) + .5(-1.33)(15)^2

x=150m
 
Thanks PN

Hey PHYSICS NOOB, I really appreciate the help. I worked the problem before coming on the forum and did'nt think that I was doing it correct. Thanks in advance again and for the fast response.
 

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