MOCO Homework: Determine Avg Velocity

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The discussion focuses on calculating the average velocity of an automatic guided vehicle that decelerates from 12 ft/sec to a stop over a distance of 18 feet. The average velocity is derived using the formula for average speed, which is the sum of initial and final speeds divided by two. The initial attempt at a solution incorrectly concludes the average velocity to be 4 ft/sec/sec, while the correct average velocity should be 6 ft/sec based on the average of the initial speed (12 ft/sec) and final speed (0 ft/sec). Participants suggest clarifying the calculation method and emphasize the importance of using the correct formula. The conversation highlights common pitfalls in understanding average velocity in deceleration scenarios.
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Homework Statement



An automatic guided vehicle is traveling at a speed of 12 ft/sec when it is ordered to stop. It uniformly decelerates to a stop in 18ft
Determine the average velocity

Homework Equations


(Initial speed-final speed)/ total time taken = decelerations

The Attempt at a Solution


avg velocity of 12 ft/sec/sec is 6
18/6 = 3
3x4 = 12
so the avg velocity is 4 ft/sec/sec
 
Last edited:
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Welcome to PF!

Hi ajayespinoza! Welcome to PF! :smile:
ajayespinoza said:
An automatic guided vehicle is traveling at a speed of 12 ft/sec when it is ordered to stop. It uniformly decelerates to a stop in 18ft
Determine the average velocity

Homework Equations


(Initial speed-final speed)/ total time taken = decelerations


The Attempt at a Solution


avg velocity of 12 ft/sec/sec is 6
18/6 = 3
3x4 = 12
so the avg velocity is 4 ft/sec/sec

(Is this the first part of a longer question? :confused:)

Hint: average speed = (Initial speed+final speed) divided by … ? :smile:
 

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