Model Rocket Impulse and momentum problem

AI Thread Summary
A model rocket with a motor providing 27.5 N·s of impulse and a mass of 0.173 kg achieves a final speed when launched from rest. The equation p = mv is used to relate momentum and velocity. By isolating the variable for velocity, the calculation shows that 27.5 N·s divided by 0.173 kg results in a speed of 159 m/sec. The discussion emphasizes the importance of correctly applying the impulse-momentum principle. Ultimately, the final speed of the rocket is confirmed to be 159 m/sec.
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A model rocket is constructed with a motor that can provide a total impulse of 27.5 N · s. The mass of the rocket is 0.173 kg. What is the speed that this rocket achieves when launched from rest? Neglect the effects of gravity and air resistance.



i know that the equation is p=mv (vector based)



0.173*v =27.5N so how do i find velocity...
 
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bchat112000 said:
A model rocket is constructed with a motor that can provide a total impulse of 27.5 N · s. The mass of the rocket is 0.173 kg. What is the speed that this rocket achieves when launched from rest? Neglect the effects of gravity and air resistance.

0.173*v =27.5N so how do i find velocity...
Hi bchat112000. http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

0.173 * v[/color] = 27.5 N·s

That's one equation with one unknown. Are you able to isolate that v[/color] pronumeral to one side by itself?
 
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yes by multiplying by both sides?
 
I love this forum by the way, thanks for helping people
 
What is your final answer for velocity?
 
i got 4.75
0.173 times 27.5n
 
ok i plugged the formula ..initial v is 0 final v is 27.5 the mass is 0.173
0+27.5=0.173 This is the formula
27.5Ns/0.173kg=159
 
bchat112000 said:
ok i plugged the formula ..initial v is 0 final v is 27.5 the mass is 0.173
0+27.5=0.173
An equals sign requires what is on one side to equal what is on the other.

This is the formula
27.5Ns/0.173kg=159
That looks better.

Speed requires both a magnitude and units

The correct answer is 159 m/sec
 
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