Modeling survival with a differential equation

PhysicsInNJ
Messages
44
Reaction score
1

Homework Statement


A health club is opened, the fraction of members still enrolled t months from their initial visit is given by the function f(t)= e-t/20. the club initially accepts 300 members and will accept new members at a rate of 10 per month. How many people will be enrolled 15 months from now.

Homework Equations


N/A

The Attempt at a Solution


I remember my professor referencing this problem could be done as a differential equation problem instead of a survival/renewal problem (which I can do).

Following the idea of inflow-outflow, I came up with

dP/dt= 10 (inflow) - ?

with P being members

I'm not sure how to take the fraction of people and make that into a rate.
Once I figure that out I could likely solve the differential normally for P.
 
Physics news on Phys.org
Okay, here's a hint. If f(t) represents the fraction of people still enrolled after their initial visit, what does 1 - f(t) represent?
 
PhysicsInNJ said:

Homework Statement


A health club is opened, the fraction of members still enrolled t months from their initial visit is given by the function f(t)= e-t/20. the club initially accepts 300 members and will accept new members at a rate of 10 per month. How many people will be enrolled 15 months from now.

Homework Equations


N/A

The Attempt at a Solution


I remember my professor referencing this problem could be done as a differential equation problem instead of a survival/renewal problem (which I can do).

Following the idea of inflow-outflow, I came up with

dP/dt= 10 (inflow) - ?

with P being members

I'm not sure how to take the fraction of people and make that into a rate.
Once I figure that out I could likely solve the differential normally for P.
Are you saying you do not know what 50% of 300 works out to? That is what you would have if ##f(t) = 0.5## applied to the initial 300.
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top