Modeling technique for Joule heating

AI Thread Summary
The discussion focuses on mathematical modeling of Joule heating in a cantilever beam. The relevance of the cantilever configuration is minimal, as the voltage connections are the primary concern. The thermal boundary condition at the cantilever's free end assumes heat loss equivalent to conduction into another connected cantilever, while convection losses to the air can be neglected. A differential equation for the system is provided, highlighting the relationship between thermal conductivity, temperature distribution, and heat generation. The conversation seeks further insights on solving this equation for temperature distribution along the beam.
jatin1990
Messages
20
Reaction score
0
Good Day, I am looking for mathematical modelling of Joule heating of a simple cantilever beam . Can anybody provide me good source of relevant material.
Thanks in advance.
 
Science news on Phys.org
What is the relevance of the beam being cantilevered? Is it that the beam is extended out into the air? What is the thermal boundary condition at the cantilever end of the beam. Do you need to include the heat transfer from the beam to the air, or is it just that the cantilever end is a heat sink at fixed temperature?

Chet
 
Thanks Chestermiller for reply, "What is the relevance of the beam being cantilevered?" good point there no practical relevance the only thing is V is connected to the fixed end and V0 is connected to the free end. "What is the thermal boundary condition at the cantilever end of the beam." Actually there is another cantilever on the other end , both are connected at the center so we can assume free end surface is loosing heat (equivalent to the actual conduction into the other cantilever) "Do you need to include the heat transfer from the beam to the air" No we can neglect the convection lose.

Thanks.
 
Chestermiller said:
What is the relevance of the beam being cantilevered? Is it that the beam is extended out into the air? What is the thermal boundary condition at the cantilever end of the beam. Do you need to include the heat transfer from the beam to the air, or is it just that the cantilever end is a heat sink at fixed temperature?

Chet

Thanks Chestermiller for reply, "What is the relevance of the beam being cantilevered?" good point there no practical relevance the only thing is V is connected to the fixed end and V0 is connected to the free end. "What is the thermal boundary condition at the cantilever end of the beam." Actually there is another cantilever on the other end , both are connected at the center so we can assume free end surface is loosing heat (equivalent to the actual conduction into the other cantilever) "Do you need to include the heat transfer from the beam to the air" No we can neglect the convection lose.
Thanks.
 
jatin1990 said:
Thanks Chestermiller for reply, "What is the relevance of the beam being cantilevered?" good point there no practical relevance the only thing is V is connected to the fixed end and V0 is connected to the free end. "What is the thermal boundary condition at the cantilever end of the beam." Actually there is another cantilever on the other end , both are connected at the center so we can assume free end surface is loosing heat (equivalent to the actual conduction into the other cantilever) "Do you need to include the heat transfer from the beam to the air" No we can neglect the convection lose.
Thanks.
The differential equation that describes this system is given by:
$$0=k\frac{d^2T}{dx^2}+Q$$
where k is the thermal conductivity, T is the temperature, x is the distance along the beam, and Q is the rate of heat generation per unit volume. Do you know how to solve this for the temperature distribution along the beam?

Chet
 
Thread 'Thermo Hydrodynamic Effect'
Vídeo: The footage was filmed in real time. The rotor takes advantage of the thermal agitation of the water. The agitation is uniform, so the resultant is zero. When the aluminum cylinders containing frozen water are immersed in the water, about 30% of their surface is in contact with the water, and the rest is thermally insulated by styrofoam. This creates an imbalance in the agitation: the cold side of the water "shrinks," so that the hot side pushes the cylinders toward the cold...
Back
Top