strangequark
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I have a problem from my modern physics class I'm hoping to get some insight on... I got an answer, but it seems, well, odd...
Inertial frame S' moves with speed v=\frac{3c}{5} in the +xdirextion past inertial frameS. Event A is a synchronizing event. Event B occurs at t=0 in Frame S and at position x'=1 meter in frame S'. Given:
For Event A:
x_{A}=0
x_{A}'=0
t_{A}=0
t_{A}'=0
For Event B:
x_{B}'=1 meter
t_{B}=0
Find,
x_{B} and t_{B}'
The relevant equations are the two lorentz transforms:
x'=\gamma(x-vt)
and
t=\gamma(t'+\frac{vx'}{c/^{2}}
For x_{B}:
Applying equation 1 I get,
\frac{x'}{\gamma}+vt=x
Then x=\frac{4}{5} meters
and for t_{B}' I get (applying equation 2),
t'=\frac{t}{\gamma}-\frac{vx'}{c^{2}}=-2.001 x 10^{-9} seconds
I'm confused about the second answer. Did I do something wrong? or does this just mean that in frame S' the event happens -2.001 x 10^{-9} seconds prior to t=0 in frame S?
Heeeeeeeelp please!
Homework Statement
Inertial frame S' moves with speed v=\frac{3c}{5} in the +xdirextion past inertial frameS. Event A is a synchronizing event. Event B occurs at t=0 in Frame S and at position x'=1 meter in frame S'. Given:
For Event A:
x_{A}=0
x_{A}'=0
t_{A}=0
t_{A}'=0
For Event B:
x_{B}'=1 meter
t_{B}=0
Find,
x_{B} and t_{B}'
Homework Equations
The relevant equations are the two lorentz transforms:
x'=\gamma(x-vt)
and
t=\gamma(t'+\frac{vx'}{c/^{2}}
The Attempt at a Solution
For x_{B}:
Applying equation 1 I get,
\frac{x'}{\gamma}+vt=x
Then x=\frac{4}{5} meters
and for t_{B}' I get (applying equation 2),
t'=\frac{t}{\gamma}-\frac{vx'}{c^{2}}=-2.001 x 10^{-9} seconds
I'm confused about the second answer. Did I do something wrong? or does this just mean that in frame S' the event happens -2.001 x 10^{-9} seconds prior to t=0 in frame S?
Heeeeeeeelp please!
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