- #1

chwala

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- Homework Statement:
- solve the modulus equation ##2|3x+4y-2|+3(25-5x+2y)^{1/2} = 0##

- Relevant Equations:
- modulus equations

##3√(25-5x+2y) = -2|3x+4y-2|##

→##9(25-5x+2y)=4[(3x+4y)^2-4(3x+4y)+4]##

→##9 (25+m)= 4[p^2-4p+4]## where ##p= 3x+4y## & ##m= 2y-5x##

##\frac{(p-2)^2}{25+m}##=## \frac{9}{4}##

→##9(25-5x+2y)=4[(3x+4y)^2-4(3x+4y)+4]##

→##9 (25+m)= 4[p^2-4p+4]## where ##p= 3x+4y## & ##m= 2y-5x##

##\frac{(p-2)^2}{25+m}##=## \frac{9}{4}##

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