Molality: Calculate Aqueous Solution Density 1g/(cm^3)

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To find the molality of an aqueous solution containing 1g/L of a protein with a molar mass of 9.0 x 10^4 g/mol, first recognize that molality is defined as moles of solute per kilogram of solvent. Given the density of the solution is 1 g/cm³, 1 liter of solution weighs 1 kg. Since the solution contains 1 g of protein, the mass of the solvent is approximately 1 kg, assuming the volume change is negligible. Therefore, the molality can be calculated using the moles of protein derived from its mass and the mass of the solvent. This approach allows for the determination of molality without needing to calculate the kilograms of solvent directly.
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How do I find the molality of an aqueous solution containing 1g/L of a certain protein with molar mass 9.0 x 10^4 g/mol if the density of the solution is 1g/(cm^3)??
 
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Molality is expressed with mole of the solute in one kilogram of solution. Try this approach first.
 
My book says molality is moles of solute over kilograms solvent.

My question/problem is how to find the kilograms of solvent
 
U needn't.Use what Chem_Tr told u and a bit of logics.Just to get u started

1g protein--------------------->1L solution
1g solution--------------------->1 cc solution

Question:
1g protein--------------------->x Kg solution...

Why didn't i pick "g solution" in the last line??Because u need to find moles protein/Kg solution...


Daniel.
 
bomba923 said:
My book says molality is moles of solute over kilograms solvent.

My question/problem is how to find the kilograms of solvent
You may assume that adding a gram of protein to a liter of water does not change its volume (or the density).
 
In that case...yes!--I can find it
 
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