Molar specific heat capacities for gases

  • Thread starter saubhik
  • Start date
  • #1
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For an isochoric process,
dV = 0
therefore dW=0
So from 1st of Thermodynamics,
dQ = dU + 0
or, n*Cp*dT = n*Cv*dT (Cp and Cv denote molar heat capacities of the gas at const pressure and volume resp.)

therefore we get Cp = Cv .(how can this be possible once we know Cp - Cv = R ?)
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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31
If you are heating at constant volume, how does dQ=ncpdT?

If dQ=dU

and dU/dT = cv, then you'll just get Q= ncvΔT
 

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