Molar specific heat capacities for gases

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SUMMARY

The discussion centers on the relationship between molar specific heat capacities for gases, specifically during an isochoric process where volume remains constant. It establishes that for such a process, the work done (dW) is zero, leading to the conclusion that the heat added (dQ) equals the change in internal energy (dU). The participants question the apparent contradiction between the derived equation Cp = Cv and the established relation Cp - Cv = R, highlighting the complexities of thermodynamic principles.

PREREQUISITES
  • Understanding of the First Law of Thermodynamics
  • Familiarity with molar heat capacities (Cp and Cv)
  • Knowledge of isochoric and isobaric processes
  • Basic principles of thermodynamics and gas laws
NEXT STEPS
  • Study the derivation of the First Law of Thermodynamics in detail
  • Explore the implications of Cp - Cv = R in various thermodynamic processes
  • Learn about isochoric and isobaric processes in real-world applications
  • Investigate the behavior of ideal gases under different thermodynamic conditions
USEFUL FOR

Students and professionals in physics and engineering, particularly those focusing on thermodynamics, heat transfer, and gas behavior in various processes.

saubhik
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For an isochoric process,
dV = 0
therefore dW=0
So from 1st of Thermodynamics,
dQ = dU + 0
or, n*Cp*dT = n*Cv*dT (Cp and Cv denote molar heat capacities of the gas at const pressure and volume resp.)

therefore we get Cp = Cv .(how can this be possible once we know Cp - Cv = R ?)
 
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If you are heating at constant volume, how does dQ=ncpdT?

If dQ=dU

and dU/dT = cv, then you'll just get Q= ncvΔT
 

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