- #1

- 642

- 160

- Homework Statement
- All below

- Relevant Equations
- All below

mx remets to mass in gram of the compost x

nx remets to moles of the compost x

nTot remets to the total moles

x remets to the additional moles of D2

I considered the molar mass:

MH2 = 2u

MHD = 3u

MD2 = 4u

10 = mH2 + mHD + mD2

10 = nH2*2 + nHD*3 + nD2*4

10 = nTot + 0.9nTot + 0.8nTot

nTot = 10/2.7

So:

0.3 = (nD2 + x)/nTot + x

x = nTot/7

x = 10/(18.9)

That is, we need to add + 10/(18.9) moles of D2,

10/(18.9) = m/4

m = 2.1 g

This seems right?