Chemistry Molecules with Microwave/Rotational spectrum

AI Thread Summary
Microwave spectroscopy is concerned with the rotational spectra of molecules, which depend on the presence of a dipole moment. Diatomic molecules like H2 and N2 lack a permanent dipole moment, thus they do not exhibit a microwave spectrum despite having rotational motion. The discussion highlights confusion about the definition of rotational spectra and the criteria for interaction with microwave radiation. It clarifies that while all molecules can rotate, only those with a dipole moment will interact with microwave photons. Therefore, molecules such as H2, N2, and O2 do not have a microwave spectrum due to their symmetrical charge distribution.
Tomtom
Messages
44
Reaction score
0

Homework Statement


This question is about microwave (rotational) spectroscopy.
Which of the following molecules have a microwave spectrum?
H2, N2, NO, N2O, CH4, CO2, OCS, H2O, Ethene, Benzene.


The Attempt at a Solution


According to my textbook, it appears that all molecules have a rotational spectrum. However, Wikipedia, "Diatomic molecules such as dioxygen (O2), dihydrogen (H2), etc. do not have a dipole moment and hence no purely rotational spectrum."

I'm not really sure what that's supposed to mean. Do all molecules have a rotational spectrum (I don't see why not, everything with a bond should be able to rotate)?

Is the rotation considered relative to one of the atoms in the molecule, or to the centre of mass?
 
Physics news on Phys.org
Have I understood it correctly if I suggest that H2, N2 and O2 all rotate, but (when not considering temporary dipoles) they should not interact with photons in the microwave (nor infrared for that matter) spectrum?
 
That would be my understanding. Both ends of the molecule interact identically, so there is no net force moment that can change rotation.

--
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top