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MoM Axial loading deformation

  1. Jul 12, 2015 #1
    1. The problem statement, all variables and given/known data
    http://prntscr.com/7rw2hj

    2. Relevant equations
    deformation = PL/AE
    A= pi/4 (d^2)

    3. The attempt at a solution
    The displacement of the shaft is equal to the summation of the displacement of each individual piece. I started on end A, and got the internal force to be 6kips
    then
    deformation at AB ~ 6x50/(9pi/4 x 18x10^3)
    = .0024 in

    for the middle shaft i got the internal force to be 2 Kips ( this could be where i am wrong, im not completely sure im doing these FBD's right.

    deformation at BC ~ 2x75/(pi x 18x10^3) ( the 4's cancel out)
    = .026

    internal load at CD is 1Kip

    deformation at CD ~ 60/(pi/4 x 18x10^3)
    = .042

    for the last two calculations, i believe they are off by a power of 10...and i cant figure out why.



    I have attached my FBD's also, thanks in advance
     

    Attached Files:

  2. jcsd
  3. Jul 12, 2015 #2
    You just did the math wrong; 2*75/(pi*18000)=.0026 not .026
     
  4. Jul 12, 2015 #3
    thats ridiculous.
    Did i have the fBD's correct?
     
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