1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

MoM Axial loading deformation

  1. Jul 12, 2015 #1
    1. The problem statement, all variables and given/known data

    2. Relevant equations
    deformation = PL/AE
    A= pi/4 (d^2)

    3. The attempt at a solution
    The displacement of the shaft is equal to the summation of the displacement of each individual piece. I started on end A, and got the internal force to be 6kips
    deformation at AB ~ 6x50/(9pi/4 x 18x10^3)
    = .0024 in

    for the middle shaft i got the internal force to be 2 Kips ( this could be where i am wrong, im not completely sure im doing these FBD's right.

    deformation at BC ~ 2x75/(pi x 18x10^3) ( the 4's cancel out)
    = .026

    internal load at CD is 1Kip

    deformation at CD ~ 60/(pi/4 x 18x10^3)
    = .042

    for the last two calculations, i believe they are off by a power of 10...and i cant figure out why.

    I have attached my FBD's also, thanks in advance

    Attached Files:

  2. jcsd
  3. Jul 12, 2015 #2
    You just did the math wrong; 2*75/(pi*18000)=.0026 not .026
  4. Jul 12, 2015 #3
    thats ridiculous.
    Did i have the fBD's correct?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted

Similar Discussions: MoM Axial loading deformation
  1. Axially Loaded (Replies: 3)

  2. Axial compressive load (Replies: 25)