Moment of Inertia around z-axis: 1-x^2, 4x+3y+2z+12

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SUMMARY

The discussion focuses on calculating the moment of inertia around the z-axis for a solid defined by the boundaries x=0, y=0, z=0, y=1-x^2, and the plane 4x+3y+2z+12. The correct interpretation of the plane equation is established as 4x+3y+2z=12, leading to the normalized equation x/3+y/4+z/6=1. The limits for x are confirmed to be from 0 to 1 in the first octant, clarifying the bounds for the integration needed to solve the problem.

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Homework Statement


Find the moment of inertia around the z-axis of the solid bounded by x=0, y=0,z=0,y=1-x^2 and 4x+3y+2z+12 assume density=1.


Homework Equations


please refer to my attachment.


The Attempt at a Solution


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You have written 4x+3y+2z+12, which I'm interpreting as 4x+3y+2z=12 => x/3+y/4+z/6=1. (All right, now I got the correct eqn from the pdf file.)

How can x go from 0 to 3? In the 1st octant, x is from 0 to 1. The rest looks OK.
 
Yes your assumption above was correct, and thank you for your assistance!
 

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