- #1

Physics lover

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- Homework Statement
- Question-:Find moment of inertia of a square of mass M and side length 'a' along an axis lying in the same plane inclined at an angle 15° to one of its sides and passing through vertex.

Help please.

- Relevant Equations
- I=Ma^2+Mr^2

Iz=Ix+Iy

My attempt-:I extended the axis and made a triangle by joining other adjacent vertex to the line such that its angles are 15°,75° and 90°.I found the distance between the centre of square and upper vertex of triangle by using law of sines.And then i found out inertia along upper vertex of triangle I=Ma^2/6+Mr^2.And then i used perpendicular axis theorem but unfortunately the answer did not match.