Moment of inertia of a right triangle

AI Thread Summary
The discussion revolves around calculating the moment of inertia of a right triangle with respect to the y-axis, given a mass of 1 kg. The user initially calculates the moment of inertia using the center of mass's y-coordinate (5/3) and arrives at a value of 25/9 or approximately 2.78 kg m². However, other participants question the correctness of this approach and suggest that the user clarify how they determined the center of mass and the relevance of the value used for "r." The conversation emphasizes the importance of accurately deriving the center of mass and understanding its application in the moment of inertia calculation.
munther
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in my homework the question wants from me to find the moment of inertia of
right triangle with the y-axis

as shown in the attatchment

note: the mass of the plate is 1 kg

i found the y coordinate of the center of mass of the plate it is 5/3
and i supposed it is the r

so the inertia will be mr^2
=1*(5/3)^2
=25/9
=2.77777 kg m^2

is that right??
 

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If you're calculating the moment of inertia with respect to the y-axis, then it doesn't look right.
 
Thank you >
but Why??

can you give me a hint??
 
munther said:
i found the y coordinate of the center of mass of the plate it is 5/3
and i supposed it is the r

I think it would be better for you to show us how you found that. Also, why do you suppose it is "the r"?
 
e(ho0n3 said:
I think it would be better for you to show us how you found that. Also, why do you suppose it is "the r"?


i found it from the first part of the question
 
munther said:
i found it from the first part of the question

Now that you found it, please post it.
 
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