Moments & Pivots: Find Force T for Level Board

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To find the upward force T required to keep a 90cm uniform board level, moments are calculated about the hinge. The weight of the board is 6N, and the moment balance equation shows that T equals 3N when the board is level, as verified by multiple forum members. The discussion also touches on the relationship between linear and angular motion, noting that in this scenario, there is no angular acceleration since the net torque sums to zero. Participants inquire about the connection between Newton's laws and angular acceleration, highlighting the parallels in their mathematical formulations. Overall, the calculations and concepts presented confirm the correctness of the derived force T.
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Homework Statement


A uniform board of length 90cm is pivoted at a hinge at one end. It is kept level by an upward vertical force T applied at the opposite end. The weight of the board is 6N. Take moments about the hinge to find T when the board is level.

Homework Equations


Moment = Force x Perpendicular distance

The Attempt at a Solution


I tried doing 45 x 6 = 270, and then 270/90 which is 3N. I think it's wrong though (I got the 45 by dividing 90 by 2)
 
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Hello Sarah, :welcome:

Much better !
What makes you doubt the result ?
Your moment balance looks like ( -45 * 6 + 90 * 3) cm * N and that is zero, so no angular acceleration.
 
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+1

Welcome to the forum. It looks right to me as well.
 
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CWatters said:
+1

Welcome to the forum. It looks right to me as well.
Thank you very much
 
How do you calculate angular acceleration, because we haven't covered it yet, and got curious.

Thank you very much for your help :)
 
Pardon the link: :smile: there is a parallel between linear motion and angular motion.
 
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Although in this case there is no angular acceleration because you were asked to arrange for the net torque to sum to zero. See also Newton's laws.
 
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BvU said:
Pardon the link: :smile: there is a parallel between linear motion and angular motion.
Thanks
 
How are Newton's Laws related to angular acceleration?

Thanks
 
  • #10
Have you come to the conclusion the answer you found in post #1 is correct ? Oh well, I hinted as much in post #2.

For Newton we have $$ \vec F = m\vec a $$ and the (almost carbon copy)https://www.boundless.com/physics/textbooks/boundless-physics-textbook/uniform-circular-motion-and-gravitation-5/angular-vs-linear-quantities-59/angular-vs-linear-quantities-272-6253/in angular motion is $$ \vec \tau = I\vec \alpha $$
(see table 1 https://www.boundless.com/physics/textbooks/boundless-physics-textbook/rotational-kinematics-angular-momentum-and-energy-9/problem-solving-88/problem-solving-techniques-332-6291/)
## \vec \tau ## is the torque
## I ## is the moment of inertia
##\vec \alpha## is the angular acceleration
 
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