Moments of Inertia Derivation,

AI Thread Summary
The discussion focuses on deriving the moment of inertia for specific objects in a homework problem. The user seeks assistance particularly with the first and fourth objects, noting that the first is similar to another problem they solved. For the fourth object, the challenge lies in integrating correctly to achieve the expected result of 1/12ML², with confusion about the limits of integration and the constant radius. Through guidance, the user realizes that when the radius is constant, it can be factored out of the integral, leading to the correct formulation of the moment of inertia. The conversation concludes with the user expressing gratitude for the help received.
Ush
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Homework Statement



I have attached the problem in one file and I have attached my attempt in the second file.
I only need help deriving the moment of inertia for the first (1) and fourth (4) objects but I have attached my solutions to the other objects in case it helps jog someones memory onto how to do this =p


Homework Equations



I = ∑miri2

A = area
M = total mass
dm = change in mass
dA = change in area
dr = change in radius

The Attempt at a Solution



attempt is attached

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Thank you for taking the time to read through my problem and helping me solve it, I appreciate your help
 

Attachments

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Number 1 is exactly the same problem as number 2, just with different limits of integration.

In number 4 note that all the mass is at the same distance from the axis.
 
I'm not sure how to integrate one so that I'll get 1/12ML2

I tried doing something similar

dm/M = dr/0.5 L because dr starts from the pivot point in the center and max dr will only cover half of the total length. After doing the integration I didn't get 1/12ML2

I still don't understand how to begin the fourth one =[
 
Ush said:
I'm not sure how to integrate one so that I'll get 1/12ML2
You've already done the integral (in #2)--the only change is the limits of integration.

I still don't understand how to begin the fourth one =[
I = ∫r2 dm. How does r vary as you move around the shell?
 
another attempt attached
 

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Ush said:
another attempt attached
For some reason, you are integrating from 0 to R/2. That's from the center of the rod to one end. But the rod goes from end to end.
 
oh wow =o I can't believe I missed that.
Thanks so much! i understand how to do the first one now =)

could you give me another hint onto how to do the fourth one?
 
Ush said:
could you give me another hint onto how to do the fourth one?
I thought I did:
Doc Al said:
How does r vary as you move around the shell?
I'll rephrase it. What's the distance from the axis of every element of mass dm as you go around the shell?
 
the distance from the axis of every element of mass, dm, is R ?
if R increases, the mass increases because you get a bigger shell

dr/R = dm/M ?? =S
 
  • #10
Ush said:
the distance from the axis of every element of mass, dm, is R ?
Exactly. Is R a variable or a constant? (For a given shell.)
 
  • #11
R is constant for a given shell
 
  • #12
Ush said:
R is constant for a given shell
Right! So simplify and complete the integral: I = ∫R2 dm
 
  • #13
if radius is constant. then mass is constant. there is no dr or dm =S
how do i sub dm for something?
 
  • #14
Ush said:
if radius is constant. then mass is constant.
Not sure what you mean. Hint: How do you deal with constants within the integral sign?
 
  • #15
if you have a constant then you take it out of the integral.
..oh my

I = ∫R2 dm
= R2∫dm
= R2 ∑m
= R2M


THANK YOU SO MUCH!
 
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