Momentum change by increasing time of impact

AI Thread Summary
Increasing the time of impact during a collision reduces the force exerted, as force is the rate of change of momentum over time. When two objects collide, their momentum is conserved, but the distribution of momentum changes based on their masses and velocities. In elastic collisions, equal masses will exchange momentum effectively, while a small mass colliding with a large mass will retain most of its momentum and change direction. The discussion clarifies that momentum is a vector quantity, meaning it has both magnitude and direction, which is crucial in understanding how momentum is transferred during collisions. Ultimately, the net momentum before and after a collision remains the same, but individual objects may experience changes in their momentum values.
beginner16
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hi, thank you for helping

For same momentum change if we increase the time of impact by factor ten then force is smaller by factor ten.

But why is that? I mean why doesn't a moving object at point of impact give away all of its momentum at the instant it hits something,no matter if that something is a wall or a ball or a piece of paper?


when two objects collide any combination of force and time could be used to produce certain impulse. What are the parameters that decide ( for specific impulse ) the amount of force two object colliding will exert on each other and the amount of time collision will last?



If two balls with same mass and speed go towards each other then momentum is zero. When they colide they both lose momentum, so how can they claim if one object loses momentum then the other object gains momentum?
I see that being true if both objects are moving in same direction or one is still. In that case one object would loose while other would gain momentum

cheers
 
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This should help explain it.
http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html#c1, or more specifically to the question
http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html#c2

Basically a force, F, is produces a change in momentum dp/dt, and assuming that mass is constant dp/dt = m dv/dt = m a where a is acceleration, which after all is a change in velocity with respect to time.

Increasing the time over which the force is applied simply reduces the acceleration, so the time rate of change of velocity (and momentum) decreases.

The masses of the bodies involved affect the rate of transfer of momentum, as well as the stiffness of the materials. But assuming purely elastic collisions (i.e. no deformation of the mass) the mass of each object involved is main factor.

If two balls with same mass and speed go towards each other then momentum is zero. When they colide they both lose momentum, so how can they claim if one object loses momentum then the other object gains momentum?
Well momentum is a vector (velocity is a vector). Depending on the coordinate system, one ball has - momentum and one has + momentum. The + momentum decreases to zero, the - momentum increases to zero. However in both cases, the magnitude of the momentum (and speed) decrease from some + value to zero.
 
The masses of the bodies involved affect the rate of transfer of momentum, as well as the stiffness of the materials. But assuming purely elastic collisions (i.e. no deformation of the mass) the mass of each object involved is main factor.

So for an object to give away all of its momentum in a moment it would have to collide with an object with large mass?
It makes sense on some intuitive level, but is there way to explain why it doesn't give away all of its momentum in a brief moment if it collides with a piece of paper or something with small mass?


However in both cases, the magnitude of the momentum (and speed) decrease from some + value to zero.

I'm not shure what you mean by that. Net momentum is same after collision as it was before the collision
 
beginner16 said:
So for an object to give away all of its momentum in a moment it would have to collide with an object with large mass?
Not quite. Assuming an elastic collision, a small mass hitting an extremely large mass will transfer very little momentum, but rather will reverse direction. The maximum transfer of momentum and kinetic energy occur when one mass hits an equal mass.

A large mass hitting a light mass keeps most of its momentum, with little or no change in direction. A light mass hitting a large mass will ricochet or recoil, retaining most of its momentum, but changing direction.

beginner16 said:
I'm not shure what you mean by that. Net momentum is same after collision as it was before the collision
The net momentum is zero before and after, but each mass has a positive 'magnitude' of momentum, p, where p = mv, where v is the speed. Speed is always positive, but velocity, which has direction can be - or +.
 
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