Momentum Flux: Quick Question (Product Rule)

[andrew.c]

Homework Statement

Heya,
I can expand the term on the LHs and get the term on the RHS no problem :)
But,
I don't understand how the bottom line is arrived at; I think its basically just a backward engineering of the product rule, but I can't get it!

Any help would be useful

 

[clamtrox]

\frac{\partial(\rho u u)}{\partial x} = \rho u \frac{\partial u}{\partial x} + u \frac{\partial (\rho u)}{\partial x}.

 

[andrew.c]

Thanks
That was easier than I thought!