How to Calculate Average Force Vectors During a Collision?

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Hi friends,
I am preparing for my exam and i am stuck with this problem, please help me out.
It won't take too long, I hope.

Homework Statement


Two bodies A and B have masses mA and mB respectively and collide completely inelastic.
Given that the mass of body A is 1200 kg and body B is 800 kg determine the avergage force vectors acting on each body during the collision. The collision itself lasts for 0.2 s.


Homework Equations


Velocity of body A: (5i + 3j) m/s
Velocity of body B: (-i + 4j) m/s

Common velocity after collision I found to be: (2.6i + 3.4j) m/s (this eq was derived in a previous question with mA = 3/2 mB)

The Attempt at a Solution


Well, I have tried using the momentum impulse theorem only to find out that the total momentum was conserved, which is good indeed. However I don't know how to find the answer I have kind of like used up my knowledge on impulse.
The answer is (-14400i + 2400j) N.
I have no clue how this answer was derived.
Please help.
 
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To find the force on a given body, use the impulse-momentum theorem:

\vec{F}\Delta t = \Delta (m\vec{v})

What's the change in momentum of body A?
 
I have tried this equation but I just seem to get -4000i+16000j. But this seems to be wrong.
Any further advice? I mean I substituted the final momentum from the initial momentum of A and divided by time, which however is initial momentum of B.
Doesnt make sense. Please help
 
Do it step by step:
(1) Find the change in velocity of A. (Final velocity minus initial.)
(2) Then find the change in momentum.
(3) Then the force.
 
Hi Doc Al,
I am really sorry for the late response but I was so busy studying that i haven't been able to check the post.
THank you very much for your help, I finally got it (actually right now). I followed your steps and I am really thankful for your help.
 
Excellent. (And you are very welcome.)
 

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