Momentum of a Doubled Cannonball with Doubled Velocity

  • Thread starter Thread starter chella
  • Start date Start date
AI Thread Summary
Momentum is defined as the product of mass and velocity, represented by P = mv. When both the mass and velocity of a cannonball are doubled, the new momentum can be calculated by substituting values, showing that it results in quadrupled momentum. Specifically, if the original mass is m and the original velocity is v, the new momentum becomes P = (2m)(2v) = 4mv. Therefore, the correct answer to the question is c) quadrupled. Understanding this relationship clarifies the concept of momentum in physics.
chella
Messages
1
Reaction score
0
Hey guys, I'm having a little trouble answering this question. At first I thought it was A, but then I started thinking in multiplying and now I"m not sure...



Momentum is inertia in motion, and it is equal to the product of a body's mass and its velocity. For example, if the speed of a projected cannonball is doubled, then the momentum is doubled. if instead the cannonball's mass is doubled, then the momentum is likewise doubled. Suppose, however, that a cannonball's mass is somehow doubled and its velocity is also doubled. Then its momentum is
a) the same
b) doubled
c) quadrupled
d) none of these


 
Physics news on Phys.org
Try to solve this by substituting some numbers if you can't see it. Say m=2 and v =2. What is the momentum? Now double both. How does the new momentum relate to the old momentum?
 
The definition of momentum (represented by P) is P = mv.

Apply this knowledge and you should have little to no problem finding the correct answer.

chella said:
Hey guys, I'm having a little trouble answering this question. At first I thought it was A, but then I started thinking in multiplying and now I"m not sure...
Momentum is inertia in motion, and it is equal to the product of a body's mass and its velocity. For example, if the speed of a projected cannonball is doubled, then the momentum is doubled. if instead the cannonball's mass is doubled, then the momentum is likewise doubled. Suppose, however, that a cannonball's mass is somehow doubled and its velocity is also doubled. Then its momentum is
a) the same
b) doubled
c) quadrupled
d) none of these
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top