Momentum of Bird on Swing after takeoff

AI Thread Summary
In a perfectly inelastic collision, a 94 kg fullback moving east at 9.0 m/s collides with a 99 kg opponent running west at 3.0 m/s. The velocity of both players after the tackle is calculated to be 2.84 m/s to the east. The decrease in kinetic energy during the collision needs to be determined by correctly calculating the initial kinetic energy of both players before the impact. The total initial kinetic energy is the sum of each player's kinetic energy, which must be calculated separately before combining. Clear communication of the momentum conservation principle is essential for solving collision problems effectively.
itsjustwhoiam
Messages
7
Reaction score
0
1.problem
A 94 kg fullback moving east with a speed of 9.0 m/s is tackled by a 99 kg opponent running west at 3.0 m/s, and the collision is perfectly inelastic.

(a) Calculate the velocity of the players just after the tackle.
___________________ m/s to the east
(b) Calculate the decrease in kinetic energy during the collision.
___________________ J2. eqns
conservation of energy/momentum
Ke=1/2 * m * v^2
Pe=mgh

The Attempt at a Solution


a. 99*3=297
94*9=846
846-297=549
549/(94+99)=2.84

b.
I AM CLUELESS? I GOT 2695.6696
 
Physics news on Phys.org
How did you get that number for part b?

If the collision is perfectly inelastic, then the two objects stick together. Since you have the velocity after impact, you can get the kinetic energy after the impact.
 
what exactly should i do?
 
You have not correctly calculated the initial kinetic energy of the the 2 players. Before the collision, each has its own mass, speed, and KE. KE is a scalar quantity. Just add them up. And your title is for the birds. :wink:
 
I don't follow your thinking for the collision. We can't talk, so we have to write very clearly. Does your teacher begin with a general statement for a collision problem such as:

momentum before collision = momentum after collision

This is most helpful and worth writing! You put the formulas on the next line (one mv for each moving object or stuck-together object), then the numbers on the next and finally the answer on the next line.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top