Momentum of Charged Particle in EM Field Explained

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Discussion Overview

The discussion centers on the momentum of a charged particle in a time-varying electromagnetic field, specifically exploring the relationship expressed as p - qA, where A represents the vector magnetic potential. The scope includes theoretical aspects and mathematical derivations related to Lagrangian and Hamiltonian mechanics, as well as special relativity.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant requests a demonstration of how the momentum of a charged particle is expressed as p - qA.
  • Another participant provides a link to a mathematical derivation based on Lagrangian/Hamiltonian mechanics.
  • A different participant inquires about the possibility of a simpler derivation for the momentum expression.
  • In response, a participant outlines a derivation using concepts from special relativity, detailing the formation of 4-vectors and the relationship between canonical and mechanical momentum.
  • The explanation includes the assertion that the sign in front of q/c A is due to the distinction between canonical momentum and mechanical momentum.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the simplicity of the derivation, as some seek a simpler explanation while others provide a more complex one based on special relativity.

Contextual Notes

The discussion includes varying levels of mathematical complexity and assumptions related to the definitions of momentum and the use of 4-vectors, which may not be fully resolved.

Master J
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Can someone demonstrate how the momentum of a charged particle in a time-varying electromagnetic field is given by

p - qA

where A is the vector magnetic potential?

I've always wondered :-)

Cheers!
 
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Thanks for that. Is there not a simpler derivation ? Surely there must be?
 
Sure, just use special relativity.

1) The quantities Pμ = (p, E/c) form a 4-vector
2) The quantities Aμ = (A, Φ) form a 4-vector
3) The total energy of the particle is E' = E + q Φ
4) E' is the 4th component of a 4-vector P'μ = (P', E')
5) It must be that P'μ = Pμ + q/c Aμ
6) Hence the other three components are P' = P + q/c A

(If you're wondering about the sign in front of q/c A, note that P' is the canonical momentum and P is the mechanical momentum.
P' = P + q/c A, but P = P' - q/c A.)
 

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