Momentum Principle. Please help (due in 1 hour 30 minutes)

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SUMMARY

The discussion revolves around solving a physics homework problem using the Momentum Principle. The initial velocity of the ball is given as <−10, 16,−5> m/s, and the y component of the ball's velocity after 0.5 seconds is calculated to be 11.1 m/s using the formula Vi - (9.8 * t). Participants are seeking assistance with subsequent parts of the problem, which include determining average velocity, maximum height, and time to reach the highest point, all based on the principles of kinematics and forces.

PREREQUISITES
  • Understanding of the Momentum Principle and its application in physics
  • Familiarity with kinematic equations and vector components
  • Knowledge of basic calculus for determining average values
  • Ability to perform calculations involving gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Learn how to apply the Momentum Principle in various scenarios
  • Study kinematic equations for projectile motion
  • Explore the concept of average velocity and its calculation
  • Investigate the relationship between time, velocity, and displacement in motion
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Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for examples of applying the Momentum Principle in problem-solving.

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Homework Statement



Part 1:

EDIT: I got part 1. The answers is 11.1m/s can anyone still help me with the others? I got 11.1 by this formula: Vi-(9.8*t)

A ball is kicked from a location on the ground
~ri = <10, 0,−8>m with initial velocity
~vi = <−10, 16,−5> m/s.
The ball’s speed is low enough that air resistance is negligible.
Find the y component of the ball’s velocity
0.5 s after being kicked. (Use the Momentum
Principle!)
Answer in units of m/s

2. In this situation (constant force), which velocity will give the most accurate value for
the location of the ball 0.5 s after it is kicked?
1. The final velocity of the ball
2. The initial velocity of the ball
3. The arithmetic mean of the initial and
final velocities

3. What is the y component of the average velocity (vector) of the ball over this time interval?
Start by finding Vavg,y.
Answer in units of m/s

4. Now use the average velocity to find the y
component of the ball’s position 0.5 s after
being kicked.
Answer in units of m

5. Now consider a different time interval: the interval between the initial kick and the moment when the ball reaches its highest point. We want to find how long it takes for the ball to reach this point, and how high the ball
goes.

What is the y component of the ball’s velocity at the instant when the ball reaches its
highest point (the end of this time interval)?
Answer in units of m/s

6. Consider the expression for the update form
of the momentum principle,
mvf,y = mvi,y + Fnet,y delta(t).
If you were to simplify this expression and
fill in all known quantities with numerical
values, what would you end up with? (Here,
vf,y refers to the y component of the ball’s
velocity at the highest point in its trajectory.)
1. 11.1 m/s = 16 m/s+(−9.8 m/s2) (0.5 s)
2. 0 = 11.1 m/s + (−9.8 m/s2)delta(t)
3. 0 = 16 m/s + (−9.8 m/s2) (0.5 s)
4. 0 = 16 m/s + (−9.8 m/s2)delta(t)
5. 11.1 m/s = 16 m/s + (−9.8 m/s2)delta(t)

7. How long does it take for the ball to reach its highest point?
Answer in units of s

8. Knowing the time you calculated in the previous parts, first find the y component of the
average velocity during this time interval, and then use it to find the maximum height attained by the ball.
Answer in units of m

Homework Equations



p=gamma(m)(v)

Momentum Principle
Pf=Pi +Fnet(delta(T))

The Attempt at a Solution



I tried using the momentum principle but I don't know where to get the final velocity from.

Any help is appreciate. I can't seem to figure out how to do this multiple question problem. It is due in about a 1 hour and 30 minutes. So please help me out if you know anyway to figure out how to do this.
 
Last edited:
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EDIT: I got part 1. The answers is 11.1m/s can anyone still help me with the others? I got 11.1 by this formula: Vi-(9.8*t)
 

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