Momentum question involving an elastic collision

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Homework Help Overview

The discussion revolves around an elastic collision problem involving two skaters with given masses and initial velocities. Participants are tasked with finding the final velocities of each skater after the collision while considering the conservation of momentum and kinetic energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the conservation of momentum and kinetic energy, with one participant attempting to set up equations based on these principles. There are discussions about verifying calculations and the correctness of derived equations.

Discussion Status

Some participants have provided feedback on the setup of equations and suggested checking calculations. There is an ongoing exploration of different methods to approach the problem, with no explicit consensus on the final answers yet.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of guidance provided. There is mention of using online calculators for verification, indicating a focus on self-checking work.

Heron
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1. A 62 kg skater traveling at 2.8 m/s accidentally bumps elastically into a 76 kg skater moving at 1.6m/s in the same direction
Find the velocity of each skater after the collision




2. m1v1 + m1v2 = m1v3 + m2v4



3.
 
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As you stated, momentum is conserved but so is one other thing. Can you figure out what?
 
Kinetic energy is also conserved.

This is all the work I have done so far.

(62)(2.8) + (76)(1.6) = 62v1 + 76v2

0.5(62)(2.8)^2 + 0.5(76)(1.6)^2 = 0.5(62)(v1)^2 + 0.5(76)(v2)^2

295.2 = 62v1 + 76v2 and 340.32 = (31)(v1)^2 + (38)(v2)^2

v2= (295.2 - 62v1)/76

340.32 = (31)(v1)^2 + (38)[(295.2 - 62v1)/76]^2

0 = (31)(v1)^2 + 357.778v1 + (25.289)(v1)^2 + 573.30947 - 340.32
 
Last edited:
It all looks good except the last line. In fact, just the term with v1 looks incorrect. Try checking the bracket expansion again?
 
I fixed it.
When I solve it I get -0.7366 and -5.6195 for v1 but neither of those are answers.
 
Heron said:
I fixed it.
When I solve it I get -0.7366 and -5.6195 for v1 but neither of those are answers.
Did you substitute these back to verify that your answers correctly solve your equation?

There is always the option of using an online calculator to check your answer, to give yourself confidence that you have the solution, e.g., http://www.quickmath.com/webMathema...+(31)(v1)^2+++(38)((295.2+-+62v1)/76)^2&v2=v1

Note: Mathematica ignores square brackets, so you must change them to round parentheses ().
 
If you set up the equation correctly, one root has to be the same as the original velocity.

You can follow a much simpler method of solving.

Arrange the equations both for momentum and energy so that the initial and final velocity of one body is at one side and those of the other body on the other side:

m1(u1-v1)=m2(v2-u2)
m1(u12-v12)=m2(v22-u22).


As v≠u for either body, you can divide the second equation with the first one, and obtain a simple first-order system of equations

u1+v1=u2+v2,
m1(u1-v1)=m2(v2-u2).


ehild
 

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