Momentum question involving vectors

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To determine the impulse needed to change a 90.0 kg football player's velocity from 3.6 m/s north to 1.2 m/s northeast, the problem involves vector subtraction of the two momentum vectors. The initial momentum is calculated as 324 kg·m/s north, while the final momentum is 90 kg multiplied by 1.2 m/s at a 45-degree angle northeast, resulting in a momentum of 108 kg·m/s northeast. The difference between these two vectors yields the required impulse, which the original poster calculated as 410 N·s at 11 degrees east of north, but the textbook answer is 259 N·s at 17 degrees east of south. The discussion emphasizes the importance of accurately representing the vectors and their directions to solve the problem correctly. Understanding vector addition and subtraction is crucial for finding the correct impulse direction and magnitude.
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Homework Statement



What impulse is needed to change the velocity of a 90.0 kg football player from 3.6 m/s towards the north and make it 1.2 m/s toward the northeast? In what direction must the force be exerted?

Homework Equations



p=mv

The Attempt at a Solution



I drew vectors of the two momentums and found the resultant momentum to be 410N.s @ 11 E of N
but the answer in the back of the book is 259N.s 17 E of S
I can't think of any other way to approach this problem...
 
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jumpyroo92 said:

Homework Statement



What impulse is needed to change the velocity of a 90.0 kg football player from 3.6 m/s towards the north and make it 1.2 m/s toward the northeast? In what direction must the force be exerted?

Homework Equations



p=mv

The Attempt at a Solution



I drew vectors of the two momentums and found the resultant momentum to be 410N.s @ 11 E of N
but the answer in the back of the book is 259N.s 17 E of S
I can't think of any other way to approach this problem...
This is a vector subtraction problem. The vector you are trying to find is the difference between the two given vectors.

What momentum vector added to the football player's momentum vector (90kg x 3.6 m/s N) gives the resultant momentum vector (ie. 90kg x 1.2 m/s N45oE)?

AM
 
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