- #1
elmosworld403
- 12
- 0
1. A student on a skateboard, with a combined mass of 78.2 kg, is moving east at 1.60 m/s. As he goes by, the student skilfully scoops his 6.4-kg backpack from the bench where he had left it. What will be the velocity of the student immediately after the pickup?
Me solving
momentum of student = momentum of student+bag
MV=MV
78.2kg(1.60 m/s E)= 84.6kg( Velocity)
125.12=84.6(Velocity)
Velocity=1.478959811
Velocity=1.5 m/s (E)
QUESTION- What I don't get is the theory behind this. How does the momentum of the student equal the momentum of student and bag? Please explain how this works.
Me solving
momentum of student = momentum of student+bag
MV=MV
78.2kg(1.60 m/s E)= 84.6kg( Velocity)
125.12=84.6(Velocity)
Velocity=1.478959811
Velocity=1.5 m/s (E)
QUESTION- What I don't get is the theory behind this. How does the momentum of the student equal the momentum of student and bag? Please explain how this works.