Momentum Transfer in 1.00kg Steel Ball Collision

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The discussion centers on calculating the momentum transferred from a 1.00 kg steel ball to the floor during a collision. The ball, initially falling from a height of 4.00 m, has a downward momentum of approximately -8.85 kg m/s before impact and an upward momentum of about 7.00 kg m/s after the collision. This leads to a proposed total momentum transfer of around 15.9 kg m/s downward. However, the book states the momentum transferred is only 1.85 kg m/s downward, which participants believe is incorrect. The consensus is that the book's answer does not align with the calculated values.
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A 1.00 kg steel ball 4.00 m above the floor is released, falls, strikes the floor, and rises to a maximum height of 2.50 m. What is the momentum transferred from the ball to the floor in the collision?

Ok the momentum down before the collision is around -8.85 kg m/s, up after the collision is about 7.00 kg m/s so shouldn't the amount of momentum transferred to the flour be around 15.9 kg m/s in the downward direction?

The book gives an answer of 1.85 kg m/s down transfered. It doesn't seem right to me. Help me out here.

Thanks
 
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Your answer seems correct to me. The book is wrong.
 
Thanks for the help!
 

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