Monostable multivibrator no input, the transistor1 in active mode?

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In summary, if T1 is in active mode all the time, there will be current flowing in RC1 and R at least, assuming the lower horizontal line is connected to a suitable voltage rail. However, if there is no negative pulse and the circuit is only powered by DC with capacitors inside, the current flow may not occur. This is a standard monostable multivibrator circuit and its operation can be easily found through a Google search.
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Outrageous
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If T1 is in active mode all the time, will there be any current flow in this circuit? ( I think it is impossible to flow) thanks
 

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If T1 is on then the circuit will remain stable until... The input on the bottom left has a capacitor in series with a diode. The first negative input pulse will charge the input capacitor and flip T1 to off, but that can happen only once.
 
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  • #3
Outrageous said:
If T1 is in active mode all the time, will there be any current flow in this circuit? ( I think it is impossible to flow) thanks
If T1 is in the active region, there will be current flowing in RC1 and R at least.

assuming the lower horizontal line is connected to a suitable voltage rail
 
  • #4
NascentOxygen said:
If T1 is in the active region, there will be current flowing in RC1 and R at least.

assuming the lower horizontal line is connected to a suitable voltage rail

If there is no pulse, and the whole is only supply with Dc and there are capacitors inside, how will the current move?
 
  • #5
NascentOxygen said:
If T1 is in the active region, there will be current flowing in RC1 and R at least.

assuming the lower horizontal line is connected to a suitable voltage rail
Thanks, guys
If there is no negative pulse ,the whole circuit is only powered by Dc ,and there are capacitor inside, how will the current flow?
 
  • #6
This sounds like a homework exercise.

It is a standard monostable multivibrator circuit. I am confident that a google search will
find its operation well-described. http://img811.imageshack.us/img811/5412/thgooglefriend1.gif
 
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1. What is a monostable multivibrator?

A monostable multivibrator is an electronic circuit that produces a single pulse or a square wave output in response to a triggering input signal. It has only one stable state and returns to that state after a certain period of time.

2. How does a monostable multivibrator work?

In a monostable multivibrator, the transistor1 is in active mode, which means it is biased in the forward direction. When a triggering input signal is applied, it causes the transistor to switch from its active state to its saturated state, producing a pulse at the output. Once the input signal stops, the transistor returns to its active state and the circuit returns to its initial stable state.

3. What is the purpose of the transistor1 in active mode?

The transistor1 in active mode acts as a switch, allowing current to flow from the power supply to the output of the circuit. When the transistor is in its active state, it is biased in the forward direction and can amplify the input signal to produce a pulse at the output.

4. How can a monostable multivibrator be used in practical applications?

Monostable multivibrators are commonly used in electronic timing circuits, such as in electronic clocks, timers, and pulse generators. They can also be used in applications where a single pulse or a square wave output is needed, such as in electronic music synthesizers or in remote control systems.

5. What are the advantages of using a monostable multivibrator?

One of the main advantages of using a monostable multivibrator is its ability to produce a precise, single pulse or square wave output. It is also a simple and cost-effective circuit, making it a popular choice in electronic systems. Additionally, it can be easily integrated into larger electronic circuits and can be used in a wide range of applications.

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