Monostable multivibrator no input, the transistor1 in active mode?

[Outrageous]

If T1 is in active mode all the time, will there be any current flow in this circuit? ( I think it is impossible to flow) thanks

 

[Baluncore]

If T1 is on then the circuit will remain stable until... The input on the bottom left has a capacitor in series with a diode. The first negative input pulse will charge the input capacitor and flip T1 to off, but that can happen only once.

 

[NascentOxygen]

If T1 is in active mode all the time, will there be any current flow in this circuit? ( I think it is impossible to flow) thanks

If T1 is in the active region, there will be current flowing^✻ in R_C1 and R at least.

^✻ assuming the lower horizontal line is connected to a suitable voltage rail[/size]

 

[Outrageous]

If T1 is in the active region, there will be current flowing^✻ in R_C1 and R at least.

^✻ assuming the lower horizontal line is connected to a suitable voltage rail[/size]

If there is no pulse, and the whole is only supply with Dc and there are capacitors inside, how will the current move?

 

[Outrageous]

If T1 is in the active region, there will be current flowing^✻ in R_C1 and R at least.

^✻ assuming the lower horizontal line is connected to a suitable voltage rail[/size]

Thanks, guys
If there is no negative pulse ,the whole circuit is only powered by Dc ,and there are capacitor inside, how will the current flow?

 

[NascentOxygen]

This sounds like a homework exercise.

It is a standard monostable multivibrator circuit. I am confident that a google search will
find its operation well-described. http://img811.imageshack.us/img811/5412/thgooglefriend1.gif