Moon earth system escape velocity

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SUMMARY

The escape velocity for a projectile fired from the moon into the Earth-moon system is determined by combining the gravitational influences of both celestial bodies. The formula for escape velocity, given as sqrt[2GM/R], applies to both the moon and Earth. To accurately calculate the total escape speed, one must account for the gravitational potential energy of both the Earth and the projectile. This comprehensive approach ensures that the escape velocity reflects the combined gravitational forces at play.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with escape velocity calculations
  • Knowledge of the mass and radius of the Earth and moon
  • Basic physics concepts related to projectile motion
NEXT STEPS
  • Research the gravitational potential energy equations for Earth and the moon
  • Learn how to calculate escape velocity for multi-body systems
  • Study the effects of gravitational forces on projectile motion
  • Explore advanced topics in celestial mechanics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and celestial dynamics, as well as educators seeking to explain escape velocity in a multi-body context.

bcjochim07
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Homework Statement


A projectile is fired straight away from the moon from a base on the far side of the moon, away from the earth. What is the projectile's escape speed from the earth-moon system?


Homework Equations


Escape velocity = sqrt[2GM/R]


The Attempt at a Solution



What I'm wondering is, do I just have to use this formula the moon or do I have to take the gravitational potential energy of the Earth and the projectile into account also?
 
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bcjochim07 said:
What I'm wondering is, do I just have to use this formula the moon or do I have to take the gravitational potential energy of the Earth and the projectile into account also?

Certainly. you need an equation for the energy needed to escape from the Earth and the moon, and you can add those energies.
 

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