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An object that bounces back with half its original speed has a final kinetic energy that is one-quarter of its initial kinetic energy, resulting in a ratio of 1:4. When a ball drops and gains 30 J of kinetic energy while accounting for air resistance, the gravitational potential energy lost is greater than 30 J. Participants in the discussion express confusion over calculating kinetic energy ratios, particularly in applying the correct formulas. The kinetic energy is derived from the formula (1/2)mv^2, and the ratio of final to initial energy must be calculated accurately. Clarifying these concepts is essential for understanding energy transformations in physics.
future_vet
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An object hits a wall and bounces back with half if its original speed. What is the ratio of the final kinetic energy to the initial kinetic energy?
I am not sure I understand the question, is it 1:2?

A ball drops some distance and gains 30 J of kinetic energy. Do not ignore air resistance. How much gravitational potential did the ball lose?
I would say more than 30J since we have to take air resistance into consideration.

Thanks!
 
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future_vet said:
An object hits a wall and bounces back with half if its original speed. What is the ratio of the final kinetic energy to the initial kinetic energy?
I am not sure I understand the question, is it 1:2?

Not so fast. Write down the kinetic energies and look at the ratio.
 
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?
 
future_vet said:
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?

No, it isn't. The first kinetic energy is 1/2 m v^2, and the second is 1/2 m (1/2 v)^2. What is their ratio?
 
future_vet said:
First is 1 and second is 0.5 => 1/0.5 =2. Is this correct?

No - the kinetic energy of the object is (1/2)mv^2.
 
I am not sure I get it, but it looks like 1:0.5 to me...
 
future_vet said:
I am not sure I get it, but it looks like 1:0.5 to me...


Do you know how to take the ratio of 1/2 m (1/2 v)^2 (final kinetic energy) and 1/2 m v^2 (initial kinetic energy)?
 
I guess not... It's ok, I'll figure it out.

Thanks!
 
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