Vic was watching a car race on TV. At the instant the flag was lowered to start the race, the picture on TV screen goes out due to surge in the power. When the picture come back on TV, the timer on score board reads 75 s. At this point Vic observes that leading car was on opposite side of the racing track (opposite side to that where racing was started). The racing track is oval in shape and 6 Km in length.
a) Determine leading cars average velocity during the time when TV was without picture?
b) What are two possible distances leading car travelled when TV was without picture?
c) Given the record for fastest racing car is 450 Km/hr, which is most likely distance-leading car has travelled when TV was without picture?
d) Based on your calculation in (c), calculate leading car average speed when TV was without picture?
v = d/t
The Attempt at a Solution
I thought maybe that half way around the track would be 3 km, but then i need the displacemet? so would that be zero?
o/75= 0 so that doesn't make sence
3/75= 0.04 m/s
004 m/s was the speed of the leading car
But now i don't know ANYTHING
I need some guidance, once i get on the right track i'll probably be able to finish the question.