Calculating Force and Torque for Moving Mass on Wheels

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To calculate the force and torque required to move a 25 kg mass at 12 m/s over 15 meters on wheels with a radius of 50 mm, the initial steps involve determining the time taken, acceleration, and applying Newton's second law. The calculations show that the time to traverse the distance is approximately 1.25 seconds, with an acceleration of 9.62 m/s², leading to a required force of 240.5 N when ignoring friction. The torque required is calculated as 12 N·m based on the force and wheel radius. It is noted that the acceleration remains independent of the friction coefficient as long as the wheels do not slip. Understanding the rotational inertia and drawing free-body diagrams are suggested for further clarity in the calculations.
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Homework Statement



Hi for all, basically I have a mass of 25Kg, want to move this mass with speed upto 12m/s for 15 meter long, where the mass held on 4 wheel (R= 50mm) and moving on aluminum alloy rails. I want to know the force needed and torque required, so I can be able to choose the suitable DC motor required.
actually I have tried most formulas but with no luck, as I don't know the friction coefficient.
However,
what is the suitable formulas are required here according to my question?
steps of calculations if possible?
Thanks in Advance.

Homework Equations


The Attempt at a Solution



1 – Find the time:
Given:
Velocity = 12 (m/s).
V: Velocity (m/s).
x: Distance (m).
t: Time (sec).
According to the rail length, which is = 14.9728 (m)
Time taken from the beginning of the rail until the end at speed of 12 (m/s) is:
t=V/x
= 1.2477 (seconds) taken from start of the rail until the end.
2- Find the acceleration:
V: Final velocity = 12(m/s)
V0: Initial velocity = 0 (m/s)
a: Acceleration (m/s2).
t: Time (seconds).
V=V0+2at
a = 9.62 (m/s2).
3- Find the Force:
Mass of the machine is 25 Kg , acceleration is 9.62 (m/s2), by using equation of motion can obtain the required force, by the following formula:
Newton second law:
F=ma
F: Force (N).
m: Mass = 25 Kg.
a: Acceleration = (m/s2).
Assume no friction "Ignore Friction":
F= 240.5 (N).
4- Find required torque:
Torque depends on force:
T = F x r sin theta ,
F= 240.5 (N)
r: wheel radius = 0.05 (m).
theta : Angle = 90.
T= 12 (N.m).
 
Last edited:
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The first thing to do is to find the acceleration of the cart given a force F. To do this, draw free-body diagrams on the wheels as well as the body, write out Newton's second law and the rotational second law, and solve. This will get quite complicated, and you'll need to make some simplifying assumptions.
 
You will, by the way, find that acceleration is independent of the coefficient of friction as long as the wheels don't slip.
 
ideasrule said:
You will, by the way, find that acceleration is independent of the coefficient of friction as long as the wheels don't slip.

it seems to complicated for me.

what about calculations that I made above ?

is it wrong ?

thanks for advance.
 
ideasrule said:
The first thing to do is to find the acceleration of the cart given a force F. To do this, draw free-body diagrams on the wheels as well as the body, write out Newton's second law and the rotational second law, and solve. This will get quite complicated, and you'll need to make some simplifying assumptions.

how to find the rotational inertia ?

thanks
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

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