- #1

toyotadude

- 18

- 0

## Homework Statement

## The Attempt at a Solution

I assumed that it was the same time going up as it was going down, and thus I had:

V(initial) = 0 m/s

a = -9.81 m/s^2

t = .84 seconds

And to solve for speed, I used the Distance = Speed x Time, thus Speed = Distance/Time... and used the Displacement = 1/2(V(initial) + V(final))*time to find the "distance", and then divide it by .84 seconds... but this was incorrect? ):