There is an S0 term missing, no? The initial displacement is 5m up... What should that equation include to show that there is an initial displacement?loku said:
Please fix that typo. Thanksloku said:
Please show me your work based on the full vertical movement equation that I posted -- it should give you a good result. We can't check your work if you don't show your work. Thanks.loku said:
berkeman said:
You seem to be substituting in variables at random. You are asked to find the initial displacement Y(t=0), so you can't plug in "5" in your initial equation for that. The initial vertical displacement in y(t) would be the unknown, and the final displacement after 5 seconds is Y(t) = 0.loku said:
Your result looks fine provided that you interpret the displacement, s, correctly.loku said:
Sure. Which variable would that be in the equation that I posted?loku said:
The equation that I posted is for 1-dimensional motion in the vertical axis with the constant acceleration of gravity acting on the object. For 2-dimensional problems, you will see an x-displacement versus time, and the general motion of the object will be an inverted parabola (like when you throw a baseball from the outfield to home plate).loku said:
That equation does not include the initial vertical displacement, so it won't help you solve a problem like this one where the final vertical position is higher or lower than the starting vertical position. That's why you need to use the full equation that I posted. Hope that helps.loku said:
Is the height of the tower negative?loku said:
No (see what I have struck out in your equation above), the initial displacement is what you are asked to find. Set y(t=5s)=0 for when it hits the ground. Initial v=5m/s, and total time when it hits the ground is t=5s. Then solve the equation for y(0).loku said:
There is initial position and final position, and the diffence between the final and initial positions is the displacement. If H is the height of the tower, the initial position is at coordinate yi=H and the final position is at yf=0. The displacement is yf-yi=-H. The OP was almost right, only he should have given the height of the tower as negative of the displacement.berkeman said:
No, the body displaces downward while you took the upward direction positive. Just change the sign of the displacement to positive, and it is the height of the tower.loku said:
No, the tower can not be that high.loku said:
5 m/s is the initial velocity.berkeman said:
You wrote in Post #2 that the "initial displacement" was 5 m.berkeman said:
Ah, you are right. Apologies to the OP!ehild said:
It cannot be. If the body were released from rest, in 5 seconds it would drop a distanceloku said:
Yes.loku said:
Motion under gravity is the movement of an object under the influence of the Earth's gravitational force. It follows a specific trajectory known as a parabolic path.
The formula for calculating displacement under gravity is: d = 1/2*g*t^2, where d is the displacement, g is the acceleration due to gravity, and t is the time elapsed.
The acceleration due to gravity on Earth is approximately 9.8 m/s^2. This means that for every second an object falls, its velocity increases by 9.8 meters per second.
The displacement under gravity is directly proportional to the square of the time elapsed. This means that as the time increases, the displacement also increases, but at a faster rate.
Yes, an object's mass can affect its displacement under gravity. The greater the mass of an object, the greater the force of gravity acting on it, and therefore, the greater the displacement will be in a given amount of time.