Motor Efficiency: Increase in Voltage & Why?

  • Thread starter Thread starter heena1988
  • Start date Start date
  • Tags Tags
    Efficiency Motor
AI Thread Summary
The discussion focuses on the efficiency of electric motors and how it relates to voltage levels. It highlights that efficiency can increase with higher voltage, but this is a misconception that needs clarification. Factors affecting motor efficiency include various loss mechanisms that prevent 100% energy conversion. The conversation emphasizes the importance of understanding different motor types and their specific characteristics. Addressing these points is crucial for accurately completing the A-level coursework.
heena1988
Messages
1
Reaction score
0
for my A level coursework i am doing the efficieny of a motor, I've just about sussed the theory:confused: . Now i have found out that the efficieny increases as the voltage increases and its wrong! :mad: i need help on saying why this would be the case. help would be much appreciated!
 
Physics news on Phys.org
Welcome to the PF, heena1988. Homework and coursework questions need to be posted here in the Homework Help forums (where I've moved your thread). And you need to show us some of your own work and thoughts in order for us to help you.

So, what factors go into the efficiency of an electric motor? There are many different types of electric motor -- which type(s) are you asked about? What are the loss mechanisms in motors (there are several) that keep the motor from being 100% efficient in converting electrical energy to mechanical energy?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top