Moving a 250kg Elephant with 425N Force

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A boy exerts a horizontal force of 425N to slide a 250kg elephant across carpeting. The net force acting on the elephant is calculated using the equation Fnet = Fap - Ff, where Ff represents the frictional force. The normal force (Fn) is equal to the gravitational force (Fg), leading to Fn = 250kg x 9.81m/s². The coefficient of kinetic friction (μk) is determined to be approximately 0.173 by dividing the applied force by the normal force. The discussion raises questions about the frictional force and its relation to the applied force.
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Homework Statement


A boy puts a 250kg elephant on a piece of carpeting and slides it across the floor by exerting a horizontal force of 425N on the elephant



Homework Equations


Ff = uKFn


The Attempt at a Solution


Fn = Fg
Fnet = Fap - Ff
Fnet = 425 - Ff
ma = 425 - uKFn
250a = 425 - uK(2450)
 
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what is the question asking?
 
for coefficient of kinetic friction
 
mue=f max/fn
425N/(250x9.81)
mue=.173

I believe that's how you do it
 
why is friction 425N
 
its force
 

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