- #1
hyddro
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Homework Statement
A square loop of side 1.5m and Resistance 2Ω is pulled with a constant velocity v=0.3m/s through a smaller region with a constant magnetic field B (out of the page) of 4T. The figure shows the position at t=0.
Calculate the magnetic flux of the coil at t=4s..
Here is a picture I made.
http://i.imgur.com/xmyfkVx.jpg
Homework Equations
E = -dFlux / dt
Magnetic flux = B*Area = B*y*x
The Attempt at a Solution
Hi,
So I tried solving this and I don't know if I am on the right track or not but I calculated the flux at t=4s. I got 3.6 T*m^2. I did this by flux = B * y*x so
flux = 4T *1.5 (high of the square) * 0.6 (part of the region that is inside the loop)
My question are first, I am not sure if I should be using 1.5 for the high, I kind of feel like i should be using the high of the region which is 0.9 but then again, they are asking for the flux through the COIL, so that's why i used 1.5 (the high). If this is correct, then why am I using 0.6 for the base? Shouldn't i be using 1.5 as well? I am confused this doesn't make any sense any help will be appreciated.