MRI Signal Intensity: Optimizing TR & TE

schulzy
Messages
5
Reaction score
0

Homework Statement


We will make a Spin-Echo experiment, and we know \rho_{w}, T1_{w},T2_{w}, \rho_{g},T1_{g},T2_{g}, where T1 and T2 are relaxation time,\rho is a proton density, and g mean gray matter, w mean white matter.
We search TR and TE, TR is a repetition time, TE is an echo time. We need this two time define, and be the different of signal intensity biggest. Signal intensity: SI=\rho\left(1-e^{-\frac{TR-TE}{T1}}\right)e^{-\frac{TE}{T2}}
also we have two equation
SI_{w}=\rho_{w}\left(1-e^{-\frac{TR-TE}{T1_{w}}}\right)e^{-\frac{TE}{T2_{w}}} and
SI_{g}=\rho_{g}\left(1-e^{-\frac{TR-TE}{T1_{g}}}\right)e^{-\frac{TE}{T2_{g}}}
and I don't know, what should I do, I divide or subtract the two equation. And after this operation we make a partial derivation:
\frac{\partial}{\partial TR}f=0 and \frac{\partial}{\partial TE}f=0
Is this place a minimum or maximum place?
Also my question is, divide I or subtract the two equation?
 
Physics news on Phys.org
Since you presumably want to differentiate grey and white matter, you want the biggest ratio of the two signals--so you divide the two equations.

The classic way to tell whether you have found a minimum or maximum is to then evaluate the 2nd derivative at the value of extremum that you found from the 1st. If the 2nd derivative is positive it's a minimum, negative = max, 0 = inflection point. Your text, it probably has additional info on extrema and 2nd derivatives.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top