Multiplicity for 3 Dimensional problem

  • Thread starter Thread starter Krazer101
  • Start date Start date
  • Tags Tags
    multiplicity
Krazer101
Messages
18
Reaction score
0

Homework Statement


I am having trouble finding an expression for W (multiplicity) for a chain that can move in all possible directions (3 dimensions)

Homework Equations


Multiplicity is the number of possible states over total states.


The Attempt at a Solution

\
I understand for a chain that can move in 1 dimension (left or right), the multiplicity is N!/(nr!(N-nr)!). N is the number of monomers the chain is made from and nr is the number of links pointing right and nl = N - nr, is the number of links pointing left. I was wondering how to find the multiplicity when the chain can movie in 3 dimensions (6 total directions)?
 
Physics news on Phys.org
If I understand the problem correctly, think about this: the multiplicity for your 1D chain is the coefficient of (x_{r})^{n_r}(x_{l})^{n_l} in the expansion of
(x_r + x_l)^N
Does that suggest anything to you? Any way to generalize this from 2 directions to 6?
 
Is it possible to raise the expansion to 3N instead of N to illustrate the other possible directions?
 
Well, remember what N represents: the number of links in the chain. If you did that, you'd be getting an expression for a chain with triple the length.

What in (x_r + x_l)^N corresponds to the number of directions?
 
Oh I see, thank you
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top