Multiplying Power Series: Help & Solutions

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Homework Help Overview

The discussion revolves around multiplying power series, specifically focusing on the product of the series for e^x and arctan(x). Participants are exploring how to properly combine these series to find the resulting power series.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the process of multiplying power series and questions whether to multiply individual terms or the entire series. Other participants suggest using the distributive property and reference the general formula for multiplying series.

Discussion Status

Participants are actively discussing the multiplication of power series, with some guidance provided on the method of combining terms. There is an acknowledgment of the complexity involved due to the infinite nature of the series, and the original poster expresses confidence in their understanding after considering the discussion.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the depth of exploration and the extent to which they can simplify the series multiplication.

mkienbau
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How do I multiply power series?

Homework Statement


Find the power series:
e^x arctan(x)

Homework Equations



e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!}

arctan(x) = 0 + x - \frac{x^3}{3} + \frac{x^5}{5} - \frac{x^7}{7}

The Attempt at a Solution



So do I multiply 1 by 0, x by x and so forth? Or do I go 1 by 0, 1 by x? Or is there another way?
 
Last edited:
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You have to multiply 1 by the whole acrtan series, x by the whole arctan series, and so on. There might be a way to simplify it though. Wikipedia has this under "power series"

f(x)g(x) = \left(\sum_{n=0}^\infty a_n (x-c)^n\right)\left(\sum_{n=0}^\infty b_n (x-c)^n\right)

= \sum_{i=0}^\infty \sum_{j=0}^\infty a_i b_j (x-c)^{i+j}

= \sum_{n=0}^\infty \left(\sum_{i=0}^n a_i b_{n-i}\right) (x-c)^n
 
So I kind of treat it like F.O.I.L.?
 
Sort of. FOIL is the distrubutive law for (binomial)X(binomial). Here, you've got two infinitely long "polynomials". Obviously, you won't be able to write out all of the terms. :-p
 
Awesome, I think I got it, I only had to take it out to the x^5 term.
 

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