Musical Tube and String (Standing wave)

AI Thread Summary
The discussion revolves around calculating the fundamental frequency of oscillation for a closed brass tube and a wire stretched at its open end. The tube's length of 1.1 m and the wire's mass of 9.6 g are key factors in determining the frequency of the air column's oscillation. The fundamental frequency can be derived using the formula f = v/(4L), where L is the length of the tube. Additionally, the tension in the wire can be calculated using the provided tension formula, which incorporates mass per unit length and total length. The participants seek guidance on applying these equations to solve the problem effectively.
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Homework Statement


A brass tube of mass 20 kg and length 1.1 m is closed at one end. A wire of mass 9.6 g and length 0.4 meters is stretched near the open end of the tube. When the wire is plucked, it oscillates at its fundamental frequency. By resonance, it sets the air column in the tube oscillating at the column's fundamental frequency.

a) What is the frequency of oscillation of the air in the tube ?

b) What is the tension in the wire?

Homework Equations


Tension=(u/(time*L)) where u is the mass/length and L is the total length


The Attempt at a Solution


I know we need natural freq. but I don't know how to find it from the given data. I think the wave length is 1.1m or some fraction of that length. Any help would be appreciated.

 
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The fundamental frequency can be surmised from the length of the tube can't it?

f = v/(4L)

Since it is the same fundamental frequency of the wire, and you know the mass/unit length of the wire, ...
 
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