Mysterious Angle X: Solving What's Smaller Than 1rad

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The discussion centers on finding an angle "X" where sinX = X and cosX = 1, with the constraint that X is less than 1 radian. The initial assumption is that the angle should be 0, as sin(0) equals 0 and cos(0) equals 1. However, the correct value is stated to be approximately 0.03 radians, which confuses the participants. They express skepticism about this result, emphasizing that plugging 0.03 into the sine and cosine functions does not yield the expected equality. The conversation highlights the need for clarification on the solution, as the participants grapple with the mathematical implications.
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Homework Statement


I was given an angle "X" with sinX=X and cosX=1. The question says that it is smaller than 1rad. Other data is irrelevant.

Homework Equations


None.


The Attempt at a Solution


In my point of view, this angle would be 0, because the only angle I know that sinOfAngle=valueOfAngle and cos=1 and at the same time smaller than 1rad. But the answer isn't 0, it's 0,03. Would someone try to explain this?
 
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No, it should be 0. I don't know where 0.03 came from.
 
I agree that it should be x=0. You can show the answer is wrong by plugging 0.03 radians into a calculator for sin(x) and cos(x).
 
JecaSpirro said:

Homework Statement


I was given an angle "X" with sinX=X and cosX=1. The question says that it is smaller than 1rad. Other data is irrelevant.

Homework Equations


None.


The Attempt at a Solution


In my point of view, this angle would be 0, because the only angle I know that sinOfAngle=valueOfAngle and cos=1 and at the same time smaller than 1rad. But the answer isn't 0, it's 0,03. Would someone try to explain this?

sin 0 is equal to x, which is 0. cos 0 is also equal to 1.
sinx = x, cosx = 1
sin (0) = (0), cos(0) = 1
 
Good news for me. Thank you all, people. Sorry to bother with a such small thing. And for my english. 8D
 
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