Need a check on a simple derivative question

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Homework Statement


If f(t)=(4t+2)/(t+3) what is f'(t)=?

The Attempt at a Solution


I got 10/(t+3)^2 but my professor insists it is 6/(t+7)^2, I know this is a simple question but I don't know where I am going wrong.
 
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You are correct.
 
mesa said:

Homework Statement


If f(t)=(4t+2)/(t+3) what is f'(t)=?

The Attempt at a Solution


I got 10/(t+3)^2 but my professor insists it is 6/(t+7)^2, I know this is a simple question but I don't know where I am going wrong.
The denominator in the derivative can't possibly be (t + 7)2. Make sure that you and your instructor are working the same problem.
 
Mark44 said:
The denominator in the derivative can't possibly be (t + 7)2. Make sure that you and your instructor are working the same problem.

That's what I told him but he has a problem listening to anyone who doesn't have Phd after their name, this is going to be fun lol!

Thanks for the verification!
 
mesa said:
That's what I told him but he has a problem listening to anyone who doesn't have Phd after their name, this is going to be fun lol!

Thanks for the verification!
I often had a "fight" with my lecturers (many of whom were professors) at university and often came out on top.

So please pursue this!

In a calm manner, of course...
 
oay said:
I often had a "fight" with my lecturers (many of whom were professors) at university and often came out on top.

So please pursue this!

In a calm manner, of course...

Oh I'm going to pursue it, this is the 'fun' part of going back to school :)

I've always been polite, although during the summer session one of my Professors asked me to please not sign up for any of his classes again, ha ha!
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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