Need help finding force components.

AI Thread Summary
The discussion revolves around solving a physics problem involving a solid sphere rolling down an incline and through a loop. The sphere starts from rest at a height h above the bottom of the loop, and the participants emphasize the need to analyze the motion in two parts: the descent down the incline and the movement through the loop. Key concepts include the application of energy conservation to determine velocity and the forces acting on the sphere, such as gravity and centripetal force. The calculations suggest that the height h must be at least 5r/2 for the sphere to successfully complete the loop. The user seeks clarification on what specific values to calculate in each part of the problem.
kambrian
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I am having a problem with this question. I can't figure out how to approach it.


A solid sphere of mass m and radius r rolls without slipping along the track. it starts from rest with the lowest point of the sphere at height h above the bottom of the loop of radius R, much larger than r.

What are the force components on the sphere at he point P if h = 3R?

How would I go about solving this problem? I attached a picture of the situation.
 

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Well you need to split up this problem. First, the sphere moves down the incline under the influence of gravity (thus, there will also be a normal force)

Then, secondly, it moves along a loop, which is circular. Then, there must be some centripetal force and also gravity right ?

regards
marlon
 
You know, just to elaborate, there is a great classic associated with this figure. Suppose we let a point particle of mass m (the solution is analoguous for a solid object, you only will need to incorporate the rotational inertia I) slide down the incline from heigth h. What will this h be as a function of radius r, in the case that the object must STOP at the top of the loop.

Well, first we study the motion along the incline : energy conservation learns us :

mgh =1/2mv² and thus v² = 2gh

Then, we study the loop : there will be both gravity and centripetal force (mv²/r) on the object. At the top : mv²/r = mg (the centripetal force must eliminate gravity. Well, actually this is the centrifugal force, directed along the opposite direction of the centripetal force) : mg = (mv²)/r and thus v² = gr

Again applying energy conservation between bottom and top of the loop learns us :

1/2mv² (here v² = 2gh) = mg2r + 1/2mv² (here v² = gr)

This eaquation gives : mgh = mg2r + mgr/2 --> h = 2r + r/2 = 5r/2

regards
marlon
 
Im still not seeing how I would do this. You said to split it up into two parts but what exactly am I trying to find in these two separate parts?

I am assuming the first part, when the ball is rolling down the incline, I am trying to find the velocity, right?
 
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