Need help in determining normal force the question is from ss krotov

AI Thread Summary
The discussion revolves around calculating the normal force exerted by a cylinder on a stationary support when the cylinder is in motion and the distance between contact points is r√2. The user attempts to apply principles of physics, including work-energy concepts and the moment of inertia, but struggles to derive the correct normal force equation. They note that friction is neglected, which simplifies the forces to be normal to the surface, and they reference the gravitational work done on the cylinder. A solution in the back of a textbook indicates that the horizontal component of the cylinder's velocity is v/2, which the user finds confusing. The thread highlights the complexities of dynamic systems and the importance of understanding velocity components in such scenarios.
ishanp
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cylinder of mass m and radius r rests on two supports of same height. one is fixed other slides with velocity v.determine normal force N by the cylinder on stationary support at the moment when distance between the point of contacts A and B of cylinder and support) is r√2assuming supports were very close to each other at the initial moment. friction between cylinder and support should be neglected.


my attempt;

r^2 +r^2=(r√2)^2

since friction is neglected the forces exerted on cylinder by supports are always normal to its surface they do zero work. only graviy does work on it. since the triangle formed by radii and AB is rt angled other angles are of 45 degree. work done till that moment=mg(r-r√2/2) . i think that the cylinder rolls without slipping about point of contact with stationary axis(A). moment of inertia about it is 3/2mr^2.if i take v=rω and put work equal to KE will get v of centre of mass and then since com moves in circle centered at A
mgcos45-N=mv^2/r ans is not coming
it is my first post here . thanks
 
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ishanp said:
cylinder of mass m and radius r rests on two supports of same height. one is fixed other slides with velocity v.determine normal force N by the cylinder on stationary support at the moment when distance between the point of contacts A and B of cylinder and support) is r√2assuming supports were very close to each other at the initial moment. friction between cylinder and support should be neglected.


my attempt;

r^2 +r^2=(r√2)^2

since friction is neglected the forces exerted on cylinder by supports are always normal to its surface they do zero work. only graviy does work on it. since the triangle formed by radii and AB is rt angled other angles are of 45 degree. work done till that moment=mg(r-r√2/2) . i think that the cylinder rolls without slipping about point of contact with stationary axis(A). moment of inertia about it is 3/2mr^2.if i take v=rω and put work equal to KE will get v of centre of mass and then since com moves in circle centered at A
mgcos45-N=mv^2/r ans is not coming
it is my first post here . thanks

problem is 1.45
solution at back says horizontal component of cylinder's velocity is v/2 .
i don't know how
 
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